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Date:2012-06-24 11:42:23

Given triangle ABC: angleA=65, angleB=n, angleC=4n. Find the measure of each angle. (Remember, the sum of the three angles of a triangle equals 180)
Given
Angle A = 65
Angle B = n
Angle C = 4n

By Angle Sum property

angle A + angle B + angle C = 180
65 + n + 4n = 180
65 + 5n = 180

subtract 65 from both side and we get;
5n = 115

divide both sides by 5 and we get;
n = 23

So, Angle B = n = 23
Angle C = 4n = 4 * 23 = 92

Hope this will help you.

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