Date:2012-02-20 13:15:51 Given two consecutive integers. The sum of two times the first integer and three times the second number is 48. Find the integers let 1st consecutive integer = x and 2nd consecutive integer = (x+1) as per the given condition- 2 (x) + 3( x + 1 ) = 48 solve parenthesis and we get; 2x + 3x + 3 = 48 5x + 3 = 48 subtract 3 from both sides and we get; 5x = 45 divide both side by 5 and we get; x = 9 so, 1st consecutive integer = x = 9 2nd consecutive integer = (9+1) = 10 hope this will help you. List of Solved Algebra Problems Write expanded form of 78, 129, 93 lita has 5 stamps more than twice the number of adels stamps. Together they have 335 stamps.. How many stamps does each one have ? Find the number such that two thirds of the number increased by one is 13 Separate 83 into two parts such that if the larger is divided by the smaller, the quotient is 4 with a remainder of 8. 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