Let 1st integer = x,
2nd integer = x+1
As per given condition
1/3x + 1/4(x+1) = 23
Solve parenthesis and we get;
1/3x + 1/4x + 1/4 = 23
(4x + 3x + 3)/12 = 23
multiply both sides by 12 and we get;
4x + 3x + 3 = 276
Add like terms and we get;
7x + 3 = 276
subtract 3 from both sides and we get;
7x = 273
Divide both side by 7 and we get;
x = 39
So, Let 1st integer = x = 39,
2nd integer = x+1 = 39 + 1 = 40 |