Let
1st consecutive number = x
2nd consecutive number = x + 2
3rd consecutive number = x + 4
4th consecutive number = x + 6
as per given condition
(x + 2) + (x + 6) = { (x) + (x + 4) } 1/2 + 17
solve parenthesis and we get;
x + 2 + x + 6 = { x + x + 4} 1/2 + 17
solve like terms
2x + 8 = {2x + 4}1/2 + 17
solve curly braces and we get;
2x + 8 = {2x + 4}1/2 + 17
2x + 8 = x + 2 + 17
2x + 8 = x + 19
2x - x = 19 - 8
x = 11
so,1st consecutive number = x = 11
2nd consecutive number = x + 2 = 11 + 2 = 13
3rd consecutive number = x + 4 = 11 + 4 = 15
4th consecutive number = x + 6 = 11 + 6 = 17
Hope this will you.. |