Given
Man's age = 35
Son's age = 7
Let the years to be found = x
As per given condition
Son's age + x = 1/2 of (man's age + x)
Put the ages of man and son and we get;
7 + x = 1/2 (35 + x)
Multiply both sides by 2 and we get;
14 + 2x = 35 + x
put like terms on one side and we get
2x - x = 35 - 14
x = 21
So, after 21 years son be half as old as his father. |