Arithmetic
Additive Identity
Arithmetic Progression
Associative Property
Averages
Brackets
Closure Property
Commutative Property
Conversion of Measurement Units
Cube Root
Decimal
Distributivity of Multiplication over Addition
Divisibility Principles
Equality
Exponents
Factors
Fractions
Fundamental Operations
H.C.F / G.C.D
Integers
L.C.M
Multiples
Multiplicative Identity
Multiplicative Inverse
Numbers
Percentages
Profit and Loss
Ratio and Proportion
Simple Interest
Square Root
Unitary Method
Algebra
Cartesian System
Order Relation
Polynomials
Probability
Standard Identities & their applications
Transpose
Geometry
Basic Geometrical Terms
Circle
Curves
Angles
Define Line, Line Segment and Rays
Non-Collinear Points
Parallelogram
Rectangle
Rhombus
Square
Three dimensional object
Trapezium
Triangle
Quadrilateral
Trigonometry
Trigonometry Ratios
Data-Handling
Arithmetic Mean
Frequency Distribution Table
Graphs
Median
Mode
Range

Videos
Solved Problems
Home >> Triangle >> Congruent Triangles >> Rules of Congruent Triangles >> RHS Rule of Congruent Triangles >>

RHS Rule of Congruent Triangles

SSS Rule of Congruent Triangles SAS Rule of Congruent Triangles ASA Rule of Congruent Triangles RHS Rule of Congruent Triangles

Before you study this topic; you are adviced to study

Define Right Angled Triangle
Define Congruence / Congruent
Congruent Triangles
Corresponding Parts of Congruent Triangles

RHS rule Congruence of right angled triangle illustrates that, if hypotenuse and one side of right angled triangle are equal to the corresponding hypotenuse and one side of another right angled triangle; then both the right angled triangle are said to be congruent.

Example: Following are two diagrams of triangle with few of its measurements:



Is △ ABC ≅ △ PQR

Solution: As shown in the given diagrams:

△ ABC is a right angled triangle at ∠ B
△ PQR is a right angled triangle at ∠ Q

Also, we have:
∠ B = ∠ Q (90° each)
BC = QR (3 cm)
AC = PR (6 cm)

Therefore, RHS congruence rules apply here and we get the following corresponding relationships:

A ↔ P
B ↔ Q
C ↔ R

Hence, △ ABC ≅ △ PQR

Justification / Proof - RHS Congruence Rule



Now, let's justify or proof of RHS Rule of Congruence with the help of following three checks:

Check 1:
There is a given right angled triangle XYZ right angled at X and length of one side XY is 5cm. You are asked to construct a triangle ABC (right angled at B) congruent to triangle XYZ.
Can you do that ??
With length of one side is given i.e. 5cm, following right angled triangles can be formed:



From the above diagram of triangles, you can observe that given triangle XYZ can be any of the following, or in other words we can say that we are not sure which diagram of triangle ABC is congruent to Triangle XYZ.

Hence, this confirms that two triangles cannot be congruent, if one side of a right angled triangle is equal to the corresponding one side of another right angled triangle.

Check 2:
There is a given right angled triangle XYZ right angled at X and length of hypotenuse YZ is 7 cm. You are asked to construct a triangle ABC (right angled at B) congruent to triangle XYZ.
Can you do that ??
With length of hypotenuse is given i.e. 7 cm, following right angled triangles can be formed:



From the above diagram of triangles, you can observe that given triangle XYZ can be any of the following, or in other words we can say that we are not sure which diagram of triangle ABC is congruent to Triangle XYZ.

Hence, this confirms that two triangles cannot be congruent, if hypotenuse of a right angled triangle is equal to the corresponding hypotenuse of another right angled triangle.

Check 3:
There is a given right angled triangle XYZ right angled at X and length of hypotenuse YZ is 7 cm and one side XY is 5 cm. You are asked to construct a triangle ABC (right angled at B) congruent to triangle XYZ.
Can you construct a triangle ABC congruent to triangle XYZ ?

Let's try to construct a triangle ABC congruent to triangle XYZ, when length of hypotenuse and one side are given.
Steps of construction are as follows:

Step 1: With the help of a protractor, draw a right angle (with right angled at B), as shown in the below diagram:



Step 2: Now with compass 5 cm wide opened and with B as center; draw an arc of which cuts one of the arm of ∠ B; as shown below:
And label point as C, at which the arc cuts arms of ∠ B; as shown below:



Therefore, we get BC = 5 cm, as shown above:

Step 3: Step 2: Now with compass 7 cm wide opened and with c as center; draw an arc of which cuts other arm of ∠ B; as shown below:
And label point as A, at which the arc cuts arms of ∠ B; as shown below:



Step 4: Join Points A and C and on checking with ruler you can observe that:
AC = 7 cm (as shown below):



Therefore resultant figure is a right angled triangle ABC with:
∠ B = 90°
BC = 5 cm
AC = 7 cm

Now you can see that:
BC ↔ XY (5 cm each)
AC ↔ ZY (7 cm each)
∠ B ↔ ∠ X (45° each)
So, on the basis above correspondence we get:
△ BCA ≅ △ XYZ

Hence, this proves RHS rule of Congruence which says:
If hypotenuse and one side of right angled triangle are equal to the corresponding hypotenuse and one side of another right angled triangle; then both the right angled triangle are said to be congruent.

Study More Solved Questions / Examples

  • Below are two right angled triangles with measurements of few parts,
    Prove △ DEF ≅ △ ZYX

  • Following diagram represents Rectangle ABCD and AC = BD. Prove △ ABC ≅ △ DCB

  • Observe the below diagram and Prove △ RPS ≅ △ QPS

  • Copyright@2022 Algebraden.com (Math, Algebra & Geometry tutorials for school and home education)