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Home >> Numbers >> Square Numbers >> Properties of Square Numbers >> Property 5 >>

Property 5 - Square Numbers

Property 1 Property 2 Property 3 Property 4 Property 5
Property 6 Property 7 Property 8

Before you understand this property, you are adviced to read:

What are Natural Numbers ?
What are Square Numbers ?

Observe the following Table 1:

Odd Square Number Sum of Two Consecutive Natural Number
9 4 + 5
25 12 + 13
49 24 + 25
81 40 + 41
121 60 + 61
169 84 + 85
225 112 + 113
289 144 + 145
361 180 + 181
441 220 + 221
529 264 + 265


In the above table 1:
Column 1 represents Odd Square numbers
Column 2 represents Sum of Consecutive Natural Numbers

Here, you can observe that in each row sum of consecutive natural numbers is equal to its corresponding odd square number.

(Note - This property does not applied to even square numbers like 4, 16, 36, 64 …. etc )

Now, learn the following two formulas to find these two consecutive natural numbers
First Consecutive Natural Number = (Square Number - 1) / 2
Second Consecutive Natural Number = (Square Number + 1) / 2


Use these formulas to solve following examples:

Example 1: Express 49 as the sum of two consecutive natural number
Solution: Given square numbers = 49
Let's find first consecutive natural and apply the above mentioned formula
First Consecutive Natural Number = (Square Number - 1) / 2

Put value of Square number and we get:
= (49 - 1) / 2

Solve bracket and we get:
= 48 / 2

Solve division expression and we get:
= 24
So, First Consecutive Natural Number = 24

Now find second consecutive natural and apply the above mentioned formula
Second Consecutive Natural Number = (Square Number + 1) / 2

Put value of Square number and we get:
= (49 + 1) / 2

Solve bracket and we get:
= 50 / 2

Solve division expression and we get:
= 25
So, Second Consecutive Natural Number = 24

Hence, 49 can be expressed as the sum of 24 and 25
(you can cross-check the answer from the above table 1)



Example 2: Express 361 as the sum of two consecutive integers
Solution: Given Odd square numbers = 361
Let's find first consecutive natural and apply the above mentioned formula
First Consecutive Natural Number = (Square Number - 1) / 2

Put value of Square number and we get:
= (361 - 1) / 2

Solve bracket and we get:
= 360 / 2

Solve division expression and we get:
= 180
So, First Consecutive Natural Number = 180

Now find second consecutive natural and apply the above mentioned formula
Second Consecutive Natural Number = (Square Number + 1) / 2

Put value of Square number and we get:
= (361 + 1) / 2

Solve bracket and we get:
= 362 / 2

Solve division expression and we get:
= 181
So, Second Consecutive Natural Number = 181

Hence, 361 can be expressed as the sum of 180 and 181
(you can cross-check the answer from the above table 1)



Example 3: Express 232 as the sum of two consecutive numbers
Solution: Convert the given numbers (232) into square number and we get:
Square Number = 529
Let's find first consecutive natural and apply the above mentioned formula
First Consecutive Natural Number = (Square Number - 1) / 2

Put value of Square number and we get:
= (529 - 1) / 2

Solve bracket and we get:
= 528 / 2

Solve division expression and we get:
= 264
So, First Consecutive Natural Number = 264

Now find second consecutive natural and apply the above mentioned formula
Second Consecutive Natural Number = (Square Number + 1) / 2

Put value of Square number and we get:
= (529 + 1) / 2

Solve bracket and we get:
= 530 / 2

Solve division expression and we get:
= 265
So, Second Consecutive Natural Number = 265

Hence, 361 can be expressed as the sum of 180 and 181
(you can cross-check the answer from the above table 1)

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