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Home >> Numbers >> Square Numbers >> Properties of Square Numbers >> Property 5 >> Property 5 - Square Numbers
Before you understand this property, you are adviced to read:
What are Natural Numbers ?
What are Square Numbers ?
Observe the following Table 1:
Odd Square Number | Sum of Two Consecutive Natural Number |
---|
9 | 4 + 5 | 25 | 12 + 13 | 49 | 24 + 25 | 81 | 40 + 41 | 121 | 60 + 61 | 169 | 84 + 85 | 225 | 112 + 113 | 289 | 144 + 145 | 361 | 180 + 181 | 441 | 220 + 221 | 529 | 264 + 265 |
In the above table 1:
Column 1 represents Odd Square numbers
Column 2 represents Sum of Consecutive Natural Numbers
Here, you can observe that in each row sum of consecutive natural numbers is equal to its corresponding odd square number.
(Note - This property does not applied to even square numbers like 4, 16, 36, 64 …. etc )
Now, learn the following two formulas to find these two consecutive natural numbers
First Consecutive Natural Number = (Square Number - 1) / 2
Second Consecutive Natural Number = (Square Number + 1) / 2
Use these formulas to solve following examples:
Example 1: Express 49 as the sum of two consecutive natural number
Solution: Given square numbers = 49
Let's find first consecutive natural and apply the above mentioned formula
First Consecutive Natural Number = (Square Number - 1) / 2
Put value of Square number and we get:
= (49 - 1) / 2
Solve bracket and we get:
= 48 / 2
Solve division expression and we get:
= 24
So, First Consecutive Natural Number = 24
Now find second consecutive natural and apply the above mentioned formula
Second Consecutive Natural Number = (Square Number + 1) / 2
Put value of Square number and we get:
= (49 + 1) / 2
Solve bracket and we get:
= 50 / 2
Solve division expression and we get:
= 25
So, Second Consecutive Natural Number = 24
Hence, 49 can be expressed as the sum of 24 and 25
(you can cross-check the answer from the above table 1)
Example 2: Express 361 as the sum of two consecutive integers
Solution: Given Odd square numbers = 361
Let's find first consecutive natural and apply the above mentioned formula
First Consecutive Natural Number = (Square Number - 1) / 2
Put value of Square number and we get:
= (361 - 1) / 2
Solve bracket and we get:
= 360 / 2
Solve division expression and we get:
= 180
So, First Consecutive Natural Number = 180
Now find second consecutive natural and apply the above mentioned formula
Second Consecutive Natural Number = (Square Number + 1) / 2
Put value of Square number and we get:
= (361 + 1) / 2
Solve bracket and we get:
= 362 / 2
Solve division expression and we get:
= 181
So, Second Consecutive Natural Number = 181
Hence, 361 can be expressed as the sum of 180 and 181
(you can cross-check the answer from the above table 1)
Example 3: Express 232 as the sum of two consecutive numbers
Solution: Convert the given numbers (232) into square number and we get:
Square Number = 529
Let's find first consecutive natural and apply the above mentioned formula
First Consecutive Natural Number = (Square Number - 1) / 2
Put value of Square number and we get:
= (529 - 1) / 2
Solve bracket and we get:
= 528 / 2
Solve division expression and we get:
= 264
So, First Consecutive Natural Number = 264
Now find second consecutive natural and apply the above mentioned formula
Second Consecutive Natural Number = (Square Number + 1) / 2
Put value of Square number and we get:
= (529 + 1) / 2
Solve bracket and we get:
= 530 / 2
Solve division expression and we get:
= 265
So, Second Consecutive Natural Number = 265
Hence, 361 can be expressed as the sum of 180 and 181
(you can cross-check the answer from the above table 1)
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