Multiplication of Like Terms

Addition of Like Terms

Subtraction of Like Terms

Multiplication of Like Terms

Before you study what is multiplication of like terms, you are advised to read: What are Like Terms ? What are Constants ? What are Variables ? How to Multiply Constant & Variable ? How to Multiply Integers ? Law of Exponent am X an = am+n Following examples will help you understand this concept: Example 1: Multiply b and b Solution: Both the terms are like terms Power of both term is 1 Now as per the Law of exponent, am X an = am+n, we get: b1 X b1 = b2 Hence, b X b = b2 Example 2: Multiply 2q and 4q Solution: As per the given question, both the given terms are like terms Write terms in the multiplication expression and we get: 2q X 4q Multiply constants and variable separately, as shown below: (2 X 4) X (q X q) Multiply constants as we multiply numbers and we get: (8) X (q X q) Multiply variables as per the Law of exponent, am X an = am+n, we get: 8 X q2 Multiply constant and variable and we get: 8q2 Hence, (2q X 4q) = 8q2 Example 3: Multiply 5a2 and 7a2 Solution: As per the given question, both the given terms are like terms Write terms in the multiplication expression and we get: 5a2 X 7a2 Multiply constants and variable separately, as shown below: (5 X 7) X (a2 X a2) Multiply constants as we multiply numbers and we get: (35) X (a2 X a2) Multiply variables as per the Law of exponent, am X an = am+n, we get: 35 X a4 Multiply constant and variable and we get: 35 a4 Hence, (5a2 X 7a2) = 35a4 Example 4: Multiply -p3 and 3p3 Solution: As per the given question, both the given terms are like terms Write terms in the multiplication expression and we get: -p3 X 3p3 Multiply constants and variable separately, as shown below: (-1 X 3 ) X (p3 X p3) Multiply constants as we multiply positive and negative integers & we get: (-3) X (p3 X p3) Multiply variables as per the Law of exponent, am X an = am+n, we get: -3 X p6 Multiply constant and variable and we get: -3p6 Hence, (-p3 X 3p3) = (-3p6) Example 5: Multiply -5ab3 and -2ab3 Solution: As per the given question, both the given terms are like terms Write terms in the multiplication expression and we get: -5ab3 X -2ab3 Multiply constants and variable separately, as shown below: (-5 X -2 ) X (a X a) X (b3 X b3) Multiply constants as we multiply two negative integers and we get: (-10) X (a X a) X (b3 X b3) Multiply variables as per the Law of exponent, am X an = am+n, we get: (-10) X (a2) X (b6) Multiply constant and variable and we get: -10a2b6 Hence, (-5ab3 X -2ab3) = (-10a2b6)