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Home >> Polynomials >> Multiplication of Polynomials >> Multiplication of Binomial & Trinomial >> Multiplication of Binomial & Trinomial
Before you understand this concept, you are advised to read:
What are Monomials & Binomials ?
What are Terms of Polynomial ?
While multiplying a binomial and a trinomial you will find following situations:
Multiply Binomial and Trinomial
Example 1: Multiply (5a + b) and (a + b + c)
Example 2: Multiply (3p - 2) and (p2 + p - 2)
Multiply Trinomial and Binomial
Example 3: Multiply (4q2 - 2q + 8) and (2q + 5)
Example 4: Multiply (a + b - c) and (z + c)
Multiply Binomial and Trinomial
Example 1: Multiply (5a + b) and (a + b + c)
Solution: As per given question:
Binomial = (5a + b)
Trinomial = (a + b + c)
Write in the multiplication expression and we get:
(5a + b) (a + b + c)
Use Distributive Law and multiply each term of Bionomial with every term of trinomial & this is done in the following steps:
= (5a X a) +(5a X b) + (5a X c) + (b X a) +(b X b) + (b X c)
= 5a2 + 5ab + 5ac + ab + b2 + bc
Rearrange the terms as shown below:
= 5a2 + b2 + 5ab + ab + 5ac + bc
Add like terms (5ab + ab = 6ab) and we get:
= 5a2 + b2 + 6ab + 5ac + bc
Hence, (5a + b) (a + b + c) = 5a2 + b2 + 6ab + 5ac + bc
Example 2: Multiply (3p - 2) and (p2 + p - 2)
Solution: As per given question:
Binomial = (3p - 2)
Trinomial = (p2 + p - 2)
Write in the multiplication expression and we get:
(3p - 2) (p2 + p - 2)
Use Distributive Law and multiply each term of Bionomial with every term of trinomial & this is done in the following steps:
= (3p X p2) + (3p X p) - (3p X 2) - (2 X p2) - (2 X p) - (2 X -2)
= 3p3 + 3p2 - 6p - 2p2 - 2p - (-4)
Since [ -(-4) = 4], so we get:
= 3p3 + 3p2 - 6p - 2p2 - 2p + 4
Rearrange the terms as shown below:
= 3p3 + 3p2 - 2p2 - 6p - 2p + 4
Solve like terms and we get:
= 3p3 + p2 - 8p + 4
Hence, (3p - 2) (p2 + p - 2) = 3p3 + p2 - 8p + 4
Multiply Trinomial and Monomial
Example 3: Multiply (4q2 - 2q + 8) and (2q + 5)
Solution: As per given question:
Trinomial = (4q2 - 2q + 8)
Binomial = (2q + 5)
Write in the multiplication expression and we get:
(4q2 - 2q + 8) (2q + 5)
Use Distributive Law and multiply each term of Bionomial with every term of trinomial & this is done in the following steps:
= (4q2 X 2q) - (2q X 2q) + (8 X 2q) + (4q2 X 5) - (2q X 5) + (8 X 5)
= 8q3 - 4q2 + 16q + 20q2 - 10q + 40
Rearrange the terms as shown below:
= 8q3 - 4q2 + 20q2 + 16q - 10q + 40
Solve like terms and we get:
= 8q3 +16q2 + 6q + 40
Hence, (4q2 - 2q + 8) (2q + 5) = 8q3 + 16q2 + 6q + 40
Example 4: Multiply (a + b - c) and (z + c)
Solution: As per given question:
Trinomial = (a + b - c)
Binomial = z + c
Write in the multiplication expression and we get:
(a + b - c) (z + c)
Use Distributive Law and multiply each term of Bionomial with every term of trinomial & this is done in the following steps:
= (a X z) + (b X z) - (c X z) + (a X c) + (b X c) - (c X c)
= az + bz - cz + ac + bc - c2
Rearrange the terms as shown below:
= (- c2 + ac + az + bc + bz - cz)
Hence, (a + b - c) (z + c) = (- c2 + ac + az + bc + bz - cz)
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