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Home >> Standard Identities & their applications >> (a + b)2 = a2 + b2 + 2ab >> Examples

A + B Whole Square : Solved Examples

(a + b)2 = a2 + b2 + 2ab (a - b)2 = a2 + b2 - 2ab a2 - b2 = (a + b) (a - b) (x + a) (x + b) = x2 + x(a + b) + ab (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(a + b)3 = a3 + b3 + 3ab(a + b) (a - b)3 = a3 - b3 - 3ab(a - b) a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)

Solve the following equations by A + B Whole Square

E) (9x + 3y)2
F) (13x + 7y)2
G) (16x + 7y)2
E) (9x + 3y)2

Apply the value to identity i.e. (a + b)2 = a2 + b2 + 2ab
(9x + 3y)2 = (9x)2 + (3y)2 + 2(9x)(3y)

Solve the exponential forms
= 81x2 + 9y2 + 2(9x)(3y)

Solve multiplication process and we get:
= 81x2 + 9y2 + 54xy

Hence (9x + 3y)2 = 81x2 + 9y2 + 54xy




F) (13x + 7y)2

Apply the value to identity i.e. (a + b)2 = a2 + b2 + 2ab
(13x + 7y)2 = (13x)2 + (7y)2 + 2(13x)(7y)

Solve the exponential forms
= 169x2 + 49y2 + 2(13x)(7y)

Solve multiplication process and we get:
= 169x2 + 49y2 + 182xy

Hence (13x + 7y)2 = 169x2 + 49y2 + 182xy




G) (16x + 7y)2

Apply the value to identity i.e. (a + b)2 = a2 + b2 + 2ab
(16x + 7y)2 = (16x)2 + (7y)2 + 2(16x)(7y)

Solve the exponential forms
= 256x2 + 49y2 + 2(16x)(7y)

Solve multiplication process and we get:
= 256x2 + 49y2 + 224xy

Hence (16x + 7y)2 = 256x2 + 49y2 + 224xy

Related Question Examples

  • Solve the following equations by A + B Whole Square

    A) (22x + 27y)2
    B) (14x + 7y)2
    C) (15x + 9y)2
    D) (18x + 4y)2
  • Solve the following equations by A + B Whole Square

    E) (9x + 3y)2
    F) (13x + 7y)2
    G) (16x + 7y)2
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