Construction of Rhombus with Compass

Area of Rhombus

Difference & Similarity between Rhombus & Rectangle

Difference & Similarity between Rhombus & Square

Difference & Similarity between Rhombus & Parallelogram

Construction of Rhombus with Compass

Before you understand this concept, you are advised to read: What is Rhombus and Diagonals of Rhombus ? How to construct Perpendicular Bisector of Line Segment ? Construction of Rhombus Here you will understand how to construct a Rhombus; where only measure of its two diagonals are given. Example: Construct Rhombus PQRS, where two diagonals PR and SQ are 5 cm and 7 cm respectively. Solution: As per the given question PR & SQ are diagonals of Rhombus PQRS PR = 5 cm SQ = 7 cm Steps of construction are as follows: Step 1: Use ruler and draw line segment SQ of 7 cm, which is also one of the diagonal (as shown below): Step 2: Use compass and draw perpendicular bisector of line segment SQ (as shown below): Note: We construct perpendicular bisector because in Rhombus, diagonals are perpendicular bisector to each other. Step 3: Mark point of intersection (line segment and perpendicular bisector) as O (as shown below): Step 4: Use compass and 2.5 cm wide open. With O as center, draw two arcs, cutting perpendicular bisector at point P and R (as shown below): Note: Here we have chosen length of 2.5 cm because in Rhombus diagonals bisect each other at point of intersection. Since length of other diagonal is 5 cm (as given), so half of 5 cm is 2.5 cm Step 5: Use ruler and join points P & S, P & Q, S & R and R & Q. And we get the resultant Rhombus PQRS (as shown below)