Construct a quadrilateral ABCD, where sides adjacent sides AB, BC, AD = 5 cm, 3 cm & 4 cm respectively. Also two included angles - Angle A and Angle B are 120 degree & 110 degree respectively.
Solution: As per given question:
AB = 5 cm
BC = 3 cm
AD = 4 cm
Angle A = 120 degree
Angle B = 110 degree
Step of construction are as follows:
Step 1: Draw as line segment AB of 5 cm (as shown below)
Step 2: Use protractor and draw angle of 120 degree at vertex A (as shown below):
( you can also draw 120 degree angle with the help of compass. To study how to construct 120 degree angle with the help of compass Click here )
Step 3: Use compass and 4 cm wide open. With A as center, draw an arc with cuts the arm of 120 degree angle; drawn in step 4. And mark point of intersection as D (as shown below)
Step 4: Use protractor and draw angle of 110 degree at vertex B (as shown below):
Step 5: Use compass and 3 cm wide open. With B as center, draw an arc with cuts the arm of 110 degree angle; drawn in step 3. And mark point of intersection as C (as shown below)
Step 6: Join point C & D and we get the resultant quadrilateral ABCD (as shown below):
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