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Home >> Equality >> Add different number >> Add different number to the sides of equality
Explanation:When different numbers are added to the sides of equation i.e. L.H.S. and R.H.S of the equation, the equality fails to hold.
Let's understand it with the help of following examples:
Example 1 - Add 5 to L.H.S. and 4 to R.H.S. of given equation and check what happens to equality
2 + 4 = 9 - 3
Solution - This proceeds as :
Add 5 to L.H.S. & 4 to R.H.S. of given equation and we get;
2 + 4 + 5 = 9 - 3 + 4
Solve L.H.S. and we get;
L.H.S. = 2 + 4 + 5
L.H.S. = 11
Solve R.H.S. and we get
R.H.S. = 9 - 3 + 4
Now solve as per BODMAS rule and we get;
R.H.S. = 10
Since L.H.S. in not equals to R.H.S i.e. 11 is not equal to 10
So the given equation 2 + 4 = 9 - 3 fails to hold equality, when we add 5 to L.H.S. and 4 to R.H.S. of given equation and hence we get that
"When different numbers are added to the sides of equation i.e. L.H.S. and R.H.S of the equation, the equality fails to hold."
Example 2 - Add 10 to L.H.S. and 5 R.H.S. of given equation and check what happens to equality
10 - 3 = 20 - 13
Solution - This proceeds as :
Add 10 to L.H.S. & 5 to R.H.S. of given equation and we get;
10 + 10 - 3 = 5 + 20 - 13
Solve L.H.S. and we get;
L.H.S. = 10 + 10 - 3
Now solve as per BODMAS rule and we get;
L.H.S. = 27
Solve R.H.S. and we get
R.H.S. = 5 + 20 - 13
Now solve as per BODMAS rule and we get;
R.H.S. = 12
Since L.H.S. in not equals to R.H.S i.e. 27 is not equal to 12
So the given equation 10 - 3 = 20 - 13 fails to hold equality, when we add 10 to L.H.S. and 5 to R.H.S. of given equation and hence we get that
"When different numbers are added to the sides of equation i.e. L.H.S. and R.H.S of the equation, the equality fails to hold."
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